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Additional Mathematics · Vector dependence and ratio reasoning

Finding a ratio from two expressions for one vector

You have two expressions for the same point, but you are not sure what to do with them.

If a vector is written in two ways, the parts in the direction of a must match, and the parts in the direction of b must match. That gives two equations for two unknowns.

This lesson opens the vector dependence and ratio reasoning set. It needs the ratio idea from solving geometric vector ratios.

Why are the coefficients allowed to match?

Vectors a and b point in different directions, so neither is a multiple of the other. Then the only way xa + yb can equal zero is x = 0 and y = 0.

Moving everything to one side of an equation turns it into that form. That is why the step is valid, and also why it fails if a and b are parallel.

Worked example: a point on AB and on a line from O

The vectors are OA = a and OB = b, with a and b not parallel. M lies on AB, and OM = μ(a + 2b) for some number μ. Find the ratio AM:MB.

Route 1, along AB. Let AM = λAB. Then OM = a + λ(b − a) = (1 − λ)a + λb.

Route 2, given. OM = μa + 2μb.

Equate coefficients.

  • Coefficient of a: 1 − λ = μ
  • Coefficient of b: λ = 2μ

Substitute the second into the first: 1 − 2μ = μ, so μ = 1/3 and λ = 2/3.

AM = (2/3)AB, so MB = (1/3)AB, and AM:MB = 2:1.

Check: OM = (1/3)a + (2/3)b. The coefficients add up to 1, so M is on AB as required.

The mistake that loses the marks

A common slip is to stop at “λ = 2/3”. The question asks for a ratio.

Step Incomplete Complete
Result λ = 2/3 λ = 2/3
Interpretation none AM = (2/3)AB, MB = (1/3)AB
Answer “2/3” AM:MB = 2:1

Another slip is to equate a coefficient of a with a coefficient of b. Keep a and b in separate columns.

Check yourself

OA = a and OB = b, with a and b not parallel. M lies on AB and OM = μ(3a + b). Find AM:MB.

Answer

Route 1: OM = (1 − λ)a + λb. Route 2: OM = 3μa + μb.

Coefficient of a: 1 − λ = 3μ. Coefficient of b: λ = μ. So 1 − λ = 3λ, which gives λ = 1/4.

Then AM = (1/4)AB and MB = (3/4)AB, so AM:MB = 1:3.

Check: OM = (3/4)a + (1/4)b, and the coefficients add up to 1.

What to study next

Next, distinguishing parallel from collinear statements in a diagram shows what you may conclude from the information in a figure. The integrated practice set tests all four lessons.

If you want a teacher to watch you choose the two routes, see online one-to-one Additional Mathematics tuition. The word-problem structure worksheet can also help you lay the routes out before you start.

Common questions

Why can I equate the coefficients of a and b?

Because a and b are not parallel. If xa + yb = 0 and a and b point in different directions, then x and y must both be zero. So when two expressions for the same vector are equal, the a parts match and the b parts match.

What if a and b are parallel?

Then you may not equate coefficients, because one vector is already a multiple of the other. Questions state that a and b are not parallel, or show a triangle in which they clearly point in different directions. Look for that statement.

How do I turn the unknown into a ratio?

If AM = λAB with M on the segment AB, then AM:MB = λ:(1 − λ). So λ = 2/3 gives AM:MB = 2/3 : 1/3, which is 2:1. Write the ratio with the points named, because the order matters.

If you can write both expressions but then stall, a one-to-one Add Maths teacher can ask the next question at the point where you stop, until the step becomes routine.

  • Online one-to-one lessons for your child with an experienced teacher.
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