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Additional Mathematics · Circular measure

Shaded regions involving sectors

You can find the sector, but the shaded part is a different shape.

A shaded region is usually one shape taken away from another, so the method is to name the pieces first. A segment is a sector minus a triangle, and a band between two radii is a large sector minus a small one.

This lesson follows arc length and sector area and is part of circular measure.

How do you split a shaded region?

Sketch the figure and label each piece. Decide whether the shaded area is a sum or a difference of the pieces, then find each piece with its own formula.

Worked example 1: a segment

A sector OAB has radius 10 cm and angle 1.2 radians. Find the area of the shaded segment between the chord AB and the arc, and its perimeter.

  1. Sector: ½ × 100 × 1.2 = 60 cm².
  2. Triangle OAB: ½ × 100 × sin 1.2 = 50 × 0.9320 = 46.60 cm².
  3. Segment: 60 − 46.60 = 13.40 cm².

Check with the direct formula: ½r²(θ − sinθ) = 50 × (1.2 − 0.9320) = 50 × 0.2680 = 13.40 cm².

For the perimeter, the arc is 10 × 1.2 = 12 cm. The chord is 2 × 10 × sin 0.6 = 11.29 cm. The perimeter is 12 + 11.29 = 23.29 cm.

Worked example 2: a band between two radii

Two sectors share centre O and angle 0.8 radians. The inner radius is 6 cm and the outer radius is 9 cm.

Area of the band: ½(9² − 6²) × 0.8 = ½ × 45 × 0.8 = 18 cm².

The mistake that costs marks

A common slip is to forget the triangle and call the sector the segment.

Step Wrong Right
Region Sector only Sector minus triangle
Working ½ × 100 × 1.2 60 − 46.60
Area 60 cm² 13.40 cm²
Size check Bigger than the shaded part in the sketch Small, like the sliver drawn

The segment in the sketch looks like a thin slice, so 60 cm² cannot be right. Comparing the answer with the sketch is the quickest check.

Check yourself

A sector has radius 12 cm and angle π/3. Find the area of the segment to 2 decimal places.

Answer

Area = ½r²(θ − sinθ) = 72 × (π/3 − sin(π/3)).

π/3 = 1.0472 and sin(π/3) = 0.8660, so the bracket is 0.1812.

Area = 72 × 0.18117 = 13.04 cm² (to 2 decimal places).

What to study next

The final lesson, circular-measure applications with consistent units, adds real-life contexts. Then test the chapter with the circular measure practice set.

The word-problem structure worksheet helps you split a figure into pieces. A teacher can guide the split in online one-to-one Additional Mathematics tuition.

Common questions

How do I find the area of a segment?

A segment is a sector minus the triangle formed by the two radii and the chord. With θ in radians, its area is ½r²θ − ½r²sinθ, which equals ½r²(θ − sinθ). Sketch the sector and triangle first to see what is removed.

What is in the perimeter of a segment?

The edge of a segment is the arc and the chord. The chord length is 2r sin(θ/2). Two radii are not part of the edge, so adding them is a common slip. List each boundary piece before adding.

How do I find the area between two sectors with the same angle?

Subtract the smaller sector from the larger: ½R²θ − ½r²θ = ½(R² − r²)θ. Take the outer radius as R and the inner radius as r. The perimeter needs both arcs and the two straight edges.

Why does my calculator give a strange value for sinθ?

It is probably in degree mode. When θ is in radians, the calculator must be in radian mode before you take sin θ. Check the mode on the screen, then recalculate and compare with a size estimate.

If you can find each shape on its own but the shaded region stops you, a one-to-one teacher can ask what the region is made of and guide you to the split.

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